45=10x^2

Solution for 45=10x^2 equation:

45=10x^2

We move all terms to the left:

45-(10x^2)=0

a = -10; b = 0; c = +45;
Δ = b2-4ac
Δ = 02-4·(-10)·45
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{2}}{2*-10}=\frac{0-30\sqrt{2}}{-20}
=-\frac{30\sqrt{2}}{-20}
=-\frac{3\sqrt{2}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{2}}{2*-10}=\frac{0+30\sqrt{2}}{-20}
=\frac{30\sqrt{2}}{-20}
=\frac{3\sqrt{2}}{-2}
$